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Write an ", StyleBox["n", FontSlant->"Italic"], " \[Times] ", StyleBox["n ", FontSlant->"Italic"], "square matrix for a conjugated system containing ", StyleBox["n", FontSlant->"Italic"], " carbons. Write", " '", StyleBox["x", FontSlant->"Italic"], "' at all diagonal positions. Write '", StyleBox["1", FontSlant->"Italic"], "' at every off-diagonal element ", StyleBox["ij", FontSlant->"Italic"], " if carbons ", StyleBox["i", FontSlant->"Italic"], " and ", StyleBox["j", FontSlant->"Italic"], " are \[Sigma]-bonded. Write '", StyleBox["0", FontSlant->"Italic"], "' at all other off-diagonal elements. The energies are related to values \ of ", StyleBox["'x'", FontSlant->"Italic"], " that make the determinant vanish by\n\n", StyleBox["E", FontSlant->"Italic"], " = \[Alpha] - ", StyleBox["x", FontSlant->"Italic"], " \[Beta]\n\n2. Write the same matrix as in #1, but write '", StyleBox["0", FontSlant->"Italic"], "' at all diagonal positions. The energies correspond to the matrix \ eigenvalues, \[Lambda], by\n\n", StyleBox["E", FontSlant->"Italic"], " = \[Alpha] + \[Lambda] \[Beta]\n" }], "Text", TextAlignment->Left], Cell[CellGroupData[{ Cell[TextData[{ "Illustration - energy calculation for allyl cation, ", Cell[BoxData[ \(TraditionalForm\`C\_1 - C\_2 - C\_3\)]] }], "Subsubtitle"], Cell[TextData[{ "Note: To define a matrix, type ", StyleBox["SHIFT-CTRL-C", FontWeight->"Bold", FontVariations->{"Underline"->True}], " and fill in the necessary information. Or, select ", StyleBox["Create Table/Matrix/Palette", FontWeight->"Bold"], " from the ", StyleBox["Input", FontWeight->"Bold"], " menu and fill in the information.\n\nMethod 1." }], "Text"], Cell[CellGroupData[{ Cell[BoxData[{ RowBox[{"m1", " ", "=", " ", RowBox[{"(", GridBox[{ {"x", "1", "0"}, {"1", "x", "1"}, {"0", "1", "x"} }], ")"}]}], "\[IndentingNewLine]", \(Solve[0 \[Equal] Det[m1], x]\)}], "Input"], Cell[BoxData[ \({{x, 1, 0}, {1, x, 1}, {0, 1, x}}\)], "Output"], Cell[BoxData[ \({{x \[Rule] 0}, {x \[Rule] \(-\@2\)}, {x \[Rule] \@2}}\)], "Output"] }, Open ]], Cell["Method 2.", "Text"], Cell[CellGroupData[{ Cell[BoxData[{ RowBox[{"m2", " ", "=", " ", RowBox[{"(", GridBox[{ {"0", "1", "0"}, {"1", "0", "1"}, {"0", "1", "0"} }], ")"}]}], "\[IndentingNewLine]", \(Eigenvalues[m2]\)}], "Input"], Cell[BoxData[ \({{0, 1, 0}, {1, 0, 1}, {0, 1, 0}}\)], "Output"], Cell[BoxData[ \({\(-\@2\), \@2, 0}\)], "Output"] }, Open ]], Cell[TextData[{ "The eigenvalues convert into these MO energies: ", StyleBox["E", FontSlant->"Italic"], " = \[Alpha] - ", Cell[BoxData[ \(TraditionalForm\`\@2\)]], "\[Beta], ", "\[Alpha] + ", Cell[BoxData[ \(TraditionalForm\`\@2\)]], "\[Beta], \[Alpha]. Because we assume \[Beta] < 0, the first energy \ corresponds to an antibonding MO, the second to a bonding MO, and the third \ to a nonbonding MO.\n" }], "Text"] }, Open ]], Cell[CellGroupData[{ Cell["Practice Problems", "Subsubtitle"], Cell[TextData[{ "Use Method 2 to obtain MO energies for ethylene and butadiene. Make sure \ you convert the eigenvalues into energies.\n\nAre the 4 pi electrons of \ butadiene stabilized compared to the 4 pi electrons found in two isolated \ ethylene molecules? (Note: the Huckel method defines the energy of a pi \ system as the ", StyleBox["sum", FontVariations->{"Underline"->True}], " of the pi electron energies.)\n\nHow do the MO energies of butadiene \ compare to those of ethylene?\n" }], "Text"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["Huckel MO Method - MOs", "Subtitle"], Cell[TextData[{ "An MO is defined by the mixing coefficients that indicate how much each AO \ contributes to the MO. The standard method for obtaining these coefficients \ is to substitute the MO energy into the secular equations, and then solve \ these equations.\n\nI haven't succeeded at making this method work in ", StyleBox["Mathematica", FontSlant->"Italic"], ". The program gives me the 'trivial' solution only: all coefficients = 0. \ Fortunately, there is another way to get the coefficients (and it's even \ simpler).\n\nThe mixing coefficients are identical to the eigenvectors of the \ 'Method 2' matrix defined above. The coefficients obtained in this way do not \ give a normalized MO, so normalization must be carried out in a second step.\n\ " }], "Text"], Cell[CellGroupData[{ Cell[TextData[{ "Illustration - energy & MO calculation for allyl cation, ", Cell[BoxData[ \(TraditionalForm\`C\_1 - C\_2 - C\_3\)]] }], "Subsubtitle"], Cell["Method 2.", "Text"], Cell[CellGroupData[{ Cell[BoxData[{ RowBox[{"m2", " ", "=", " ", RowBox[{"(", GridBox[{ {"0", "1", "0"}, {"1", "0", "1"}, {"0", "1", "0"} }], ")"}]}], "\[IndentingNewLine]", \(Eigensystem[m2]\)}], "Input"], Cell[BoxData[ \({{0, 1, 0}, {1, 0, 1}, {0, 1, 0}}\)], "Output"], Cell[BoxData[ \({{\(-\@2\), \@2, 0}, {{1, \(-\@2\), 1}, {1, \@2, 1}, {\(-1\), 0, 1}}}\)], "Output"] }, Open ]], Cell[TextData[{ "The output from the ", StyleBox["Eigensystem", FontWeight->"Bold"], " function is complicated and must be read carefully. The first list \ contains the eigenvalues {\[Lambda]1, \[Lambda]2, \[Lambda]3}. The subsequent \ lists contain the eigenvectors corresponding to each of these eigenvalues, \ respectively:\n\n", Cell[BoxData[GridBox[{ {"\[Lambda]", "evector"}, {\(-\@2\), \({1, \(-\@2\), 1}\)}, {\(\@2\), \({1, \@2, 1}\)}, {"0", \({\(-1\), 0, 1}\)} }, GridFrame->True]]], "\n\nThese results transform into MO energies and ", StyleBox["unnormalized", FontVariations->{"Underline"->True}], " MOs as follows:\n\n", Cell[BoxData[GridBox[{ {"E", "MO"}, {\(\[Alpha] - \(\(\@2\) \(\[Beta]\)\(\ \)\)\), \(p\_1 - \(\@2\) p\_2 + p\_3\)}, {\(\[Alpha] + \(\@2\) \[Beta]\), \(p\_1 + \(\@2\) p\_2 + p\_3\)}, {"\[Alpha]", \(p\_1 - p\_3\)} }, GridFrame->True]]], "\n\nTo normalize the MOs, recall that the Huckel MO method assumes ", StyleBox["no overlap", FontVariations->{"Underline"->True}], " between different ", StyleBox["p", FontSlant->"Italic"], " orbitals. This greatly simplifies the overlap integral. For example,\n\n\ ", Cell[BoxData[ \(TraditionalForm\`1\ = \(\[Integral]\((\[Phi]\_3)\)\^2\ = \ \(\ \[Integral]\(\(N\^2\)(p\_1 - \(\@2\) p\_2 + p\_3)\)\^2\ = \ \(N\^2\)[\ \[Integral]\((p\_1)\)\^2\ + \ 2 \(\[Integral]\((p\_2)\)\^2\)\ + \ \ \[Integral]\((p\_3)\)\^2]\)\)\)]], "\n\n\t", Cell[BoxData[ \(TraditionalForm\`\(\(=\)\(\ \)\(\(N\^2\)(1\ + \ 2\ + \ 1)\ = \ 4\ N\^2\)\)\)]], "\n\nWhich gives ", StyleBox["N", FontSlant->"Italic"], " = 1/2 and ", Cell[BoxData[ \(TraditionalForm\`\[Phi]\_3\ = \ \((1/2)\) \((p\_1 - \(\@2\) p\_2 + p\_3)\)\)]], "\n\nIn general, the normalization constant for any Huckel MO can be \ obtained as follows:\n\n", Cell[BoxData[ \(TraditionalForm\`\[Phi]\ = \ N \(\[Sum]\(c\_i\) p\_i\)\)]], "\n\n", Cell[BoxData[ \(TraditionalForm\`N\ = \ 1/\@\(\[Sum]\ c\_i\^2\)\)]], "\n" }], "Text"] }, Open ]], Cell[CellGroupData[{ Cell["Practice Problems", "Subsubtitle"], Cell[TextData[{ "Obtain eigenvectors for ethylene and butadiene. Transform these into \ normalized MOs.\n\n", StyleBox["Spartan", FontSlant->"Italic"], " images of the MOs are shown on the front screen. How do the signs of the \ mixing coefficients correlate with interatomic nodes?" }], "Text"] }, Open ]] }, Open ]] }, FrontEndVersion->"5.2 for Microsoft Windows", ScreenRectangle->{{0, 1024}, {0, 685}}, WindowSize->{726, 512}, WindowMargins->{{24, Automatic}, {Automatic, 30}}, PrintingCopies->1, PrintingPageRange->{Automatic, Automatic} ] (******************************************************************* Cached data follows. If you edit this Notebook file directly, not using Mathematica, you must remove the line containing CacheID at the top of the file. The cache data will then be recreated when you save this file from within Mathematica. *******************************************************************) (*CellTagsOutline CellTagsIndex->{} *) (*CellTagsIndex CellTagsIndex->{} *) (*NotebookFileOutline Notebook[{ Cell[CellGroupData[{ Cell[1776, 53, 47, 0, 76, "Subtitle"], Cell[1826, 55, 1453, 50, 437, "Text"], Cell[CellGroupData[{ Cell[3304, 109, 156, 4, 44, "Subsubtitle"], Cell[3463, 115, 394, 12, 151, "Text"], Cell[CellGroupData[{ Cell[3882, 131, 263, 7, 114, "Input"], Cell[4148, 140, 67, 1, 41, "Output"], Cell[4218, 143, 88, 1, 46, "Output"] }, Open ]], Cell[4321, 147, 25, 0, 47, "Text"], Cell[CellGroupData[{ Cell[4371, 151, 243, 6, 114, "Input"], Cell[4617, 159, 67, 1, 41, "Output"], Cell[4687, 162, 52, 1, 46, "Output"] }, Open ]], Cell[4754, 166, 448, 14, 125, "Text"] }, Open ]], Cell[CellGroupData[{ Cell[5239, 185, 40, 0, 44, "Subsubtitle"], Cell[5282, 187, 514, 10, 255, "Text"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell[5845, 203, 42, 0, 76, "Subtitle"], Cell[5890, 205, 782, 13, 359, "Text"], Cell[CellGroupData[{ Cell[6697, 222, 161, 4, 71, "Subsubtitle"], Cell[6861, 228, 25, 0, 47, "Text"], Cell[CellGroupData[{ Cell[6911, 232, 243, 6, 114, "Input"], Cell[7157, 240, 67, 1, 41, "Output"], Cell[7227, 243, 112, 2, 77, "Output"] }, Open ]], Cell[7354, 248, 2218, 60, 908, "Text"] }, Open ]], Cell[CellGroupData[{ Cell[9609, 313, 40, 0, 44, "Subsubtitle"], Cell[9652, 315, 305, 7, 151, "Text"] }, Open ]] }, Open ]] } ] *) (******************************************************************* End of Mathematica Notebook file. *******************************************************************)